©Richard Lowry, 1999-
All rights reserved.
Aha! says the investigator. The null hypothesis here is that the distance from the top of a person's head to the horizontal surface on which he or she erectly stands is unrelated to whether the person is wearing shoes. I, on the other hand, have begun with the directional hypothesis that people are in fact taller with shoes on than with shoes offand the outcome of my experiment is clearly consistent with that hypothesis. On average, my subjects were 1.6 inches taller when they had their shoes on than when they took them off. Moreover, each individual subject, without exception, was taller with shoes on than with shoes off.
Subject
Sample A
shoes on
Sample B
shoes off
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
64.8
70.5
69.3
55.5
61.4
69.7
68.8
64.6
63.8
61.9
69.4
63.0
75.5
69.4
59.1
63.5
68.8
67.6
54.1
59.9
68.6
66.7
63.0
61.8
59.4
68.4
61.1
73.9
68.2
58.1
mean
65.8
64.2
MA MB = 1.6
SS
378.4
384.1
variance
25.2
25.6
standard
deviation
±5.0
±5.1
| t | = | MXaMXb est.i | Formula for independent-samples t-test, from Ch. 11. |
From this point on, the logic of the situation will be familiar. If there were no tendency for people to be taller with shoes than without, then we would expect the mean of the
Subject
Sample A
shoes on
Sample B
shoes off
Di
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
64.8
70.5
69.3
55.5
61.4
69.7
68.8
64.6
63.8
61.9
69.4
63.0
75.5
69.4
59.1
63.5
68.8
67.6
54.1
59.9
68.6
66.7
63.0
61.8
59.4
68.4
61.1
73.9
68.2
58.1
+1.3
+1.7
+1.7
+1.4
+1.5
+1.1
+2.1
+1.6
+2.0
+2.5
+1.0
+1.9
+1.6
+1.2
+1.0
Recall thatx
Di=XAi XBi
MD
1.6
SSD
2.59
variance
0.17
standard
deviation
±0.42
| An alternative correlated-samples design in this scenario would be by way of matched pairs. Subjects could be pre-tested on sensory-motor coordination and then sorted out in pairs, each subject being matched with another who has the closest pre-test level of sensory-motor coordination. Within each pair, one subject would then be randomly assigned to group A and the other to group B. In this event, the heading of the first column in the following table would be "Pair" instead of "Subject." |
In the column of D-values, a positive sign indicates that the subject's performance on the task was better in condition A than in condition B, while a negative sign indicates the opposite. As you can see, the negative signs preponderate, suggesting at first glance that sensory-motor coordination is on average better with music of
Music Type
Subject
A
B
Di
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
10.2
8.4
17.8
25.2
23.8
25.7
16.2
21.5
21.1
16.9
24.6
20.4
25.8
17.1
14.4
13.2
7.4
16.6
27.0
27.5
26.6
18.0
21.2
23.4
21.1
23.8
20.2
29.1
17.7
19.2
.3.0
+1.0
+1.2
.1.8
.3.7
.0.9
.1.8
+0.3
.2.3
.4.2
+0.8
+0.2
.3.3
.0.6
.4.8
Recall thatx
Di=XAi XBi
MD
.1.53
SSD
55.45
variance
3.70
standard
deviation
±1.92
| (1) | According to the null hypothesis, the values of Di in the sample derive from a source population whose mean is |
|
i |
| (2) | If we knew the variance of the source population, we would then be able to calculate the standard deviation ("standard error") of the sampling distribution of MD as |
| x | [ | x N | ] | From Ch.9, Pt.1 |
| (3) | This, in turn, would allow us to test the null hypothesis for any particular instance of MD by calculating the appropriate |
| z = | MD
| From Ch.9, Pt.1 |
| (3) | and referring the result to the unit normal distribution.
In actual practice, however, the variance of the source population of |
| t | = | MD est.i | From Ch.9, Pt.2 |
| (3) | The resulting value belongs to the particular sampling distribution of t that is defined by |
| (3) | For this next point, recall that the relevant numerical values for the present example are |
| As indicated in Chapter 9, the variance of the source population can be estimated as
| |
| {s2} | = | SSD N1 | From Ch.9, Pt.2 |
| (3) | which for the present example comes out as |
| {s2} | = | 55.45 14 | = 3.96 |
| (3) | This, in turn, allows us to estimate the standard deviation of the sampling distribution of MD as |
| est.i | [ | {s2} N | ] | From Ch.9, Pt.2
|
| = sqrt | [ | 3.96 | 15 ] | = ±0.51 | |
| (4) | The estimated value ofi |
| it | =i | MD est.i
|
| = | .1.53 | 0.51 = 3.0 with df=14 | |
| Note that this test makes the following assumptions and can be meaningfully applied only insofar as these assumptions are met: That the scale of measurement for XA and XB has the properties of an equal-interval scale. That the values of Di have been randomly drawn from the source population. That the source population from which the values of Di have been drawn can be reasonably supposed to have a normal distribution. |
| MD = | i Ni |
| SSD =i | (i iNi |
| {s2} | = | SSD N1 |
| est. | =i | sqrti | [ | {s2} iNi | ] |
| est. | =i | sqrti | [ | SSD/(N1) iNi | ] |
| it | =i | MD est.i |
So as not to leave you lying awake at night wondering about it, I'll conclude by noting that if you were to apply the correlated-samples |
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