©Richard Lowry, 1999-
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| Subject | A | B | C| 1 |
subj1 under | condition A
subj1 under | condition B
subj1 under | condition C Each row represents one subject measured under each of k conditions. 2 |
subj2 under | condition A
subj2 under | condition B
subj2 under | condition C 3 |
subj3 under | condition A
subj3 under | condition B
subj3 under | condition C And so on. | | ||||
| Block | A | B | C| 1 |
subj1a under | condition A
subj1b under | condition B
subj1c under | condition C Each row includes k matched subjects, each measured under one or another of the k conditions 2 |
subj2a under | condition A
subj2b under | condition B
subj2c under | condition C 3 |
subj3a under | condition A
subj3b under | condition B
subj3c under | condition C And so on. | | ||||
![]() Courtesy of Lafayette Instruments |
|
| Conditions ("cps"=clicks per second) Sub- | jects A | [0cps] B | [2cps] C | [6cps]
| Subject | Means 1 | 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
35 | 32 33 32 31 29 29 27 27 28 27 27 24 24 17 17 14 13
39 | 35 32 32 33 30 31 29 31 27 27 26 29 25 16 15 15 13
32 | 31 28 29 26 29 27 27 24 24 23 23 19 19 18 17 12 13
35.3 | 32.7 31.0 31.0 30.0 29.3 29.0 27.7 27.3 26.3 25.7 25.3 24.0 22.7 17.0 16.3 13.7 13.0 Group | Means 25.9 | 26.9 | 23.4 | | |||
| Please keep in mind that the data in this example are completely imaginary. I do not know whether an actual experiment of this sort would produce a pattern of group means resembling the one shown here. |
| A [0cps] | B [2cps] | C [6cps] | All groups combined
| Na=18 | 12800 Nb=18 | 14021 Nc=18 | 10443 NT=54 | 37264 |
| A [0cps] | B [2cps] | C [6cps] | All groups combined
| SSa=735.8
| SSb=952.9
| SSc=596.3
| SST=2405.0
|
|
(If it is not clear where the four values of SS are coming from, | click here for an account of the computational details.) | ||||
| SSwg | = SSa + SSb + SSc
|
|
| = 735.8 + 952.9 + 596.3
|
|
| = 2285.0
| |
| SSbg | = SST SSwg
|
|
| = 2405.0 2285.0
|
|
| = 120.0
| |
As illustrated by the following diagram, the aggregate differences
Here again it is a good idea to check the accuracy of one's calculations up to this point by also fetching SSbg through the computational formula
SSbg
=
( Xai)2
Na
+
( Xbi)2
Nb
+
( Xci)2
Nc
( XTi)2
NT
=
(466)2
18
+
(485)2
18
+
(421)2
18
(1372)2
54
=
120.0
|
SST=2405.0
SSbg=120.0 SSwg=2285.0 |
|
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