©Richard Lowry, 1999-
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| gumpies | sticklebarbs | spotheads | Totals| Observed frequency | of cases 89 | (29.7%) 120 | (40.0%) 91 | (30.3%) 300 | Expected frequency | of cases (MCE) 100 | (33.3%) 100 | (33.3%) 100 | (33.3%) 300 | |
| observed frequencyexpected frequency expected frequency |
| gumpies: | (89100) 100 | = .11
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|
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| sticklebarbs: | (120100) | 100 = +.20
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|
|
| spotheads: | (91100) | 100 = .09
| | |||||
| (observed frequencyexpected frequency)2 expected frequency |
| gumpies: | (89100)2 100 | = 1.21 |
| ||||||||
| sticklebarbs: | (120100)2 100 | = 4.0
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|
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| spotheads: | (91100)2 | 100 = .81
| | |||
| (observed frequencyexpected frequency)2 expected frequency | = | (OE)2 E |
| gumpies: | (89100)2/100 = 1.21
|
| sticklebarbs:
| (120100)2/100 = 4.0
|
| spotheads:
| (91100)2/100 = .81
| |
| (OE)2 E |
| = 1.21 + 4.0 + .81 = 6.02 |
| If the proportions of the three fish species in the river were still actually one-third each, how likely is it that this or any other random sample of size N=300 might end up with a discrepancy between the observed and expected frequency patterns this large or larger; that is, with a calculated chi-square value equal to or greater than 6.02? |
Generate a series of a's, b's, and c's, such that the probability of each is exactly one-third. Label each instance of a as a "gumpie," each instance of b as a "sticklebarb," and each instance of c as a "spothead." Count up the respective frequencies of the three species within the sample of 300 and calculate and record the value of chi-square, using the expected frequency of E=100 for each cell. Go back to the beginning and repeat this operation for a total of 10,000 times. |
| gumpies | sticklebarbs | spotheads| O | 89 | 120 | 91 | E | 100 | 100 | 100 | |
| gumpies | sticklebarbs | spotheads| O | 120 | 89 | 91 |
| O | 89 | 91 | 120 | | |||||
| a | b|
| + | = 20 | |
| a | b | c|
| + | + | = 20 | |
Level of Significance (non-directional test)| df | 1 2 3 4 5 10 11 .05 | 3.84 5.99 7.81 9.49 11.07 18.31 19.68 .025 | 5.02 7.38 9.35 11.14 12.83 20.48 21.92 .01 | 6.63 9.21 11.34 13.28 15.09 23.21 24.73 .005 | 7.88 10.60 12.84 14.86 16.75 25.19 26.76 .001 | 10.83 13.82 16.27 18.47 20.52 29.59 31.26 | |||||||||||||
Illustration for df=2
|
If the observed value | of chi-square is: smaller than 5.99 equal to 5.99 greater than 5.99 equal to 7.38 greater than 7.38 equal to 9.21 greater than 9.21 etc.
| Then it is: non-significant significant at the .05 level significant beyond the .05 level significant at the .025 level significant beyond the .025 level significant at the .01 level significant beyond the .01 level etc. | |
| strongly disagree 9.4% | moderately disagree 15.6% | undecided 34.3% | moderately agree 27.5% | strongly agree 13.2% |
| strongly disagree | moderately disagree | undecided | moderately agree | strongly agree | Total| O | 28 | (13.7%) 34 | (16.7%) 50 | (24.5%) 57 | (27.9%) 35 | (17.2%) 204 | E | 19.2 | (9.4%) 31.8 | (15.6%) 70.0 | (34.3%) 56.1 | (27.5%) 26.9 | (13.2%) 204 |
| (OE)2 | E
(2819.2)2 | 19.2 =4.03
(3431.8)2 | 31.8 =0.15
(5070)2 | 70 =5.71
(5756.1)2 | 56.1 =0.01
(3526.9)2 | 26.9 =2.44 12.34
| df=4 | | |||||||||||||
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